Asked by Greg
The point P lies in the 4th quadrant and is located on a circle of radius 2. Find the missing coordinate for P. (___, (negative square root of 3)).
Answers
Answered by
Reiny
so you given y = -√3
x^2 + y^2 = 2^2
x^2 + 3 = 4
x^2 = 1
x = ± 1 , but the point is in IV
so x = 1
x^2 + y^2 = 2^2
x^2 + 3 = 4
x^2 = 1
x = ± 1 , but the point is in IV
so x = 1
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