Question

C4 H10 O or diethyl ether or with a formula of CH3CH2OCH2CH3 its stick structure is
H H H H
! ! ! ! ..
H-C-C-C-C- O-H
! ! ! ! ..
H H H H
I used the this ! sign as a sign for bond. pls help me to determine the geometry for each central atom in this structure.
1) C Trigonal
2) C Tetrahedral
3) O bent
4) C tetrahedral
5) C tetrahedral
pls correct my work did i do the lewis structure right are my answers to each central atom's molecular geometry right.

Answers

DrBob222
Well, you note quickly that the spacing doesn't work on thhis forum.
First you did not draw a Lewis structure nor did you attempt to draw one. The Lewis structure, better known as the Le3wis dot structure has electrons instead of the bonds. I can't draw that on this forum but here is a link that may help.
http://en.wikipedia.org/wiki/Ether
The hybridization for all of the C atoms is sp3 which makes them tetrahedral. The hybridization of the O atom is sp3 so it is tetrahedral.
One way I remember is this.
Count the bonds on C.
4 bonds--sp3 -- tetrahedral
3 bons (as in -C=C-) sp2 = trigonal planar.
2 bonds (as in -CtripleC-) = sp = linear
This holds for N as well.

Related Questions