Asked by allie
The boiling point of diethyl ether CH3CH2OCH2CH3 is 34.500C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is cholesterol .
How many grams of cholesterol, C27H46O (386.6 g/mol), must be dissolved in 263.0 grams of diethyl ether to raise the boiling point by 0.4500C ?
How many grams of cholesterol, C27H46O (386.6 g/mol), must be dissolved in 263.0 grams of diethyl ether to raise the boiling point by 0.4500C ?
Answers
Answered by
DrBob222
delta T = Kb*molality. You know delta T and Kb (somewhere in the problem or you have a table containing the information), solve for molality.
Then molality = moles/kg solvent, you know m and kg solvent, calculate moles.
Then moles = grams/molar mass, calculate grams.
and molality = moles/kg solvent.
Then molality = moles/kg solvent, you know m and kg solvent, calculate moles.
Then moles = grams/molar mass, calculate grams.
and molality = moles/kg solvent.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.