Asked by Dee

A 2000 kg car is slowed down uniformly from 18.0 m/s to 5.00 m/s in 4.20 s. (a) What average total force acted on the car during that time? (b) How far did the car travel during that time?
Answered by Elena
v=v₀-at
a= (v₀-v)/t
(a)
F=ma
(b)
s= v₀t-at²/2
There are no AI answers yet. The ability to request AI answers is coming soon!