Ask a New Question

Question

A 607-kg elevator starts from rest and moves upward for 4.40 s with constant acceleration until it reaches its cruising speed, 1.73 m/s.

(a) What is the average power of the elevator motor during this period?
.


(b) How does this amount of power compare with its power during an upright trip with constant speed?
W
13 years ago

Answers

Related Questions

A 685 kg elevator starts from rest and moves upward for 2.80 s with constant acceleration until it r... A 645-kg elevator starts from rest and reaches a cruising speed of 1.47 m/s after 3.13 seconds. It m... A 645-kg elevator starts from rest. It moves upward for t = 3.13 s with a constant acceleration unt... A 690 kg elevator starts from rest. It moves upward for 2.56 s with constant acceleration until it r... A(n) 563 kg elevator starts from rest. It moves upward for 3.18 s with a constant acceleration until... A 500 kg elevator starts from rest. It moves upward for 4.00 s with constant acceleration until it r... An elevator starts out at the 1st floor. It goes up 4 floors, down 2 floors, up 5 floors, down 3 flo... An elevator starts from the first floor upwards. The height h in meters above the first floor after...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use