Asked by toor
A fighter-jet is in level flight at an altitude of 400m and with a speed of 200m/s. The fighter launches a rocket-powered missile horizontally from the underside of the jet. The rocket engine provided a constant horizontal acceleration of 25.0 m/s^2.
a) how far does the missile travel horizontally from the launch point to impact with the ground?
b) calculate the components of the missile's impact velocity.
a) how far does the missile travel horizontally from the launch point to impact with the ground?
b) calculate the components of the missile's impact velocity.
Answers
Answered by
Elena
x: v(x) = v₀ +at,
x= v₀•t+at²/2,
y: v(y) = gt,
h=gt²/2,
t=sqrt(2h/g) = sqrt(2•400/9.8)= 9.04 s.
v(y) = gt = 9.8•9.04 =88.6 m/s,
v(x) = v₀ +at = 200+25•9.04=426 m/s.
s= 200•9.04 + 25•9.04²/2 = 2829.5 m.
x= v₀•t+at²/2,
y: v(y) = gt,
h=gt²/2,
t=sqrt(2h/g) = sqrt(2•400/9.8)= 9.04 s.
v(y) = gt = 9.8•9.04 =88.6 m/s,
v(x) = v₀ +at = 200+25•9.04=426 m/s.
s= 200•9.04 + 25•9.04²/2 = 2829.5 m.
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