A 3.00-kg block starts from rest at the top of a 27.5° incline and slides 2.00 m down the incline in 1.20 s.

Question

(a) Find the acceleration of the block.
m/s2

(b) Find the coefficient of kinetic friction between the block and the incline.


(c) Find the frictional force acting on the block.
N

(d) Find the speed of the block after it has slid 2.00 m.
m/s

Answer 1

on the incline, the block has a normal to the incline component (mg*cosTheta), and a component of gravity force down the plane(mg*sinTheta)


a. Vf=at , but Vf^2=2ad, so
(at)^2=2ad
a=2d/t^2

b. Forcedown=mg*sinTheta-mu*mg(cosTheta)
but f=ma, so
ma= stuff to right, solve for mu.

c. Forcedown=mg*sinTheta-frictionforce

d. friction force= mu*mg(cosTheta)

Answer 2

silly