Asked by sammeh
need help with this question please
a 1kg block starts at rest and slides down the incline. the coefficient of friction between the incline and the block is 0.1. The height of the incline is 2m, and the angle is 30 degrees. use energy consideration to find the block's speed at the bottom of the incline. (5.6m/s)
a 1kg block starts at rest and slides down the incline. the coefficient of friction between the incline and the block is 0.1. The height of the incline is 2m, and the angle is 30 degrees. use energy consideration to find the block's speed at the bottom of the incline. (5.6m/s)
Answers
Answered by
bobpursley
The friction is the thing to work.
Friction down the plane is .1*mg*cosTheta
Weight down the plane is mgSinTheta
FinalKE=initialPE- forcefriction*distance
Initial PE is mg*2m*sin30
Friction down the plane is .1*mg*cosTheta
Weight down the plane is mgSinTheta
FinalKE=initialPE- forcefriction*distance
Initial PE is mg*2m*sin30
Answered by
sammeh
how do you find the distance? is it 2/sin30?
Answered by
sammeh
I cannot get 5.6m/s
this is what i did.
finalKE = initial PE - Ff*d
(1/2)mv^2 = 9.8 - (.8487 x 4)
v= 3.5
this is what i did.
finalKE = initial PE - Ff*d
(1/2)mv^2 = 9.8 - (.8487 x 4)
v= 3.5
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