An object is launched horizontally from a cliff. The cliff is 80m high and the object has an initial velocity of 50m/s. Find the initial x and y velocity and the final x and y velocity

Answer 1

Xo = 50 m/s
Yo = 0.

h = Vo*t + 0.5g*t^2 = 80 m.
0 + 4.9t^2 = 80
t^2 = 16.33
Tf = 4.04 s. = Fall time.

Y = Yo + gt = 0 + 9.8*4.04 = 39.6 m/s =
Final Y velocity.

X = 50 m/s = Final X velocity

NOTE: The hor. component of velocity does not change.