To find a three-digit number where the sum of its digits is equal to one-fifth of the product of its digits, we can use a simple step-by-step approach.
Let's consider the three-digit number as ABC, where A, B, and C represent the hundreds, tens, and units digits, respectively.
1. Start with the hundreds digit (A). Since we want the sum of the digits to be one-fifth of the product of the digits, we have A + B + C = (A * B * C) / 5.
2. Begin by trial and error. Start with values for A, B, and C and check if the equation holds true. Remember, A, B, and C must be nonzero digits.
3. For example, let's start with A = 1, B = 2, and C = 3.
Plugging these values into the equation, we get 1 + 2 + 3 = (1 * 2 * 3) / 5, which simplifies to 6 = 6/5. Since the equation is not true, we need to try a different combination.
4. Continue this process, trying different values for A, B, and C until we find a combination that satisfies the equation.
Using this method, you may find that there is no three-digit number that meets the given condition. However, if there is such a number, you will eventually find it by systematically testing different combinations of values for A, B, and C.