Asked by Danica
A compound has the empirical formula CH2O. When 0.0866 g is dissolved in 1.0 g of ether, the solution’s boiling pint is 36.5oC. Determine the molecular formula of this substance
Answers
Answered by
DrBob222
Look up the normal boiling point of ether. Then delta T is difference between normal boiling point and 36.5.
delta T = Kf*m
Substitute and solve for m = molality.
Molality = mols/kg solvent. 1g ether = 0.001 kg. Solve for mols.
Then mols = grams/molar mass. You know mols and grams, solve for molar mass.
Finally, molar mass/empirical mass = some number. Round to the nearest whole number which I'll call n and apply to this.
(CH2O)<sub>n</sub>
delta T = Kf*m
Substitute and solve for m = molality.
Molality = mols/kg solvent. 1g ether = 0.001 kg. Solve for mols.
Then mols = grams/molar mass. You know mols and grams, solve for molar mass.
Finally, molar mass/empirical mass = some number. Round to the nearest whole number which I'll call n and apply to this.
(CH2O)<sub>n</sub>
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