Asked by Justin
A compound has the empirical formula CHCl. A 256 mL flask, at 373 K and 750. torr, contains 0.800 g of the gaseous compound. Give the molecular formula.
Answers
Answered by
DrBob222
Use PV = nRT and solve for n.
Then n = grams/molar mass
Solve for molar mass.
Divide molar mass/empirical mass and round to a whole number which I will call x. Then (CHCl)x will be the molecular formula.
Then n = grams/molar mass
Solve for molar mass.
Divide molar mass/empirical mass and round to a whole number which I will call x. Then (CHCl)x will be the molecular formula.
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