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Asked by Lily

Three consecutive integers have a sum of 357. Fid the integers algebraically.

I know the three numbers are 118, 119, and 120 but how do you write it in an algebraic expression ?
13 years ago

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Answered by Ms. Sue
x + x + 1 + x + 2 = 357

3x + 3 = 357

3x = 357 - 3

3x = 354

x = 118



13 years ago
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Three consecutive integers have a sum of 357. Fid the integers algebraically.

I know the three numbers are 118, 119, and 120 but how do you write it in an algebraic expression ?

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