Asked by Melissa
Each dividend was divided by another polynomial, resulting in the given quotient and remainder. Find the divisor
Divided:5x^3+x^2+3 ,quotient:5x^2-14x+42, remainder:-123
Divided:5x^3+x^2+3 ,quotient:5x^2-14x+42, remainder:-123
Answers
Answered by
Steve
we know that
5x^3+x^2+3 = p(x)*(5x^2-14x+42) - 123
so,
5x^3 + x^2 + 126 = p(x)*(5x^2 - 14x + 42)
a simple long division yields p(x) = (x+3)
5x^3+x^2+3 = p(x)*(5x^2-14x+42) - 123
so,
5x^3 + x^2 + 126 = p(x)*(5x^2 - 14x + 42)
a simple long division yields p(x) = (x+3)
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