Asked by mark
.A 5.5kg riffle fires an 11gram bullet with a velocity of 1000m/s.
a. find the velocity of a riffle?
b. if the shooter holds the riffle firmly with his shoulder what will be the velocity assume the mass of shooter is 120kg?
a. find the velocity of a riffle?
b. if the shooter holds the riffle firmly with his shoulder what will be the velocity assume the mass of shooter is 120kg?
Answers
Answered by
bobpursley
Use conservation of momentum to solve this.
Answered by
MacSy_
Solution
*Let,
m1= 0.011 kg
v1= 1000 m/s
m2=5.5 kg and
v2= be the recoil velocity
*Equation:
M1V1+M2V2=0
a. (0.011 kg)(1000 m/s) + (5.5 kg)(v2)=0
11 kgm/s + 5.5 kgv2 = 0
5.5 kgv2 = -11 kg
v2= -2 m/s
b. (0.011 kg)(1000 m/s) + (120 kg + 5.5 kg)(v2)=0
11 kgm/s + 125.5 kgv2 = 0
125.5 kgv2 = -11 kgm/s
V2= -0.9 m/s or -9 cm/s
*Let,
m1= 0.011 kg
v1= 1000 m/s
m2=5.5 kg and
v2= be the recoil velocity
*Equation:
M1V1+M2V2=0
a. (0.011 kg)(1000 m/s) + (5.5 kg)(v2)=0
11 kgm/s + 5.5 kgv2 = 0
5.5 kgv2 = -11 kg
v2= -2 m/s
b. (0.011 kg)(1000 m/s) + (120 kg + 5.5 kg)(v2)=0
11 kgm/s + 125.5 kgv2 = 0
125.5 kgv2 = -11 kgm/s
V2= -0.9 m/s or -9 cm/s
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