Asked by Tane
You toss a rock up vertically at an initial speed of 34 feet per second and release it at an initial height of 6 feet. The rock will remain in the air for how many seconds?
Answers
Answered by
Steve
h(t) = 6 + 34t - 16t^2
h=0 when t = 1/16 (17 + √385) = 2.29 seconds
h=0 when t = 1/16 (17 + √385) = 2.29 seconds
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