Asked by Andrea
                Aspirin (C9H8O4) is synthesized by the reaction of salicylic acid (C7H6O3) with acetic anhydride, C4H6O3.
2C7H6O3 + C4H6O3 −→ 2C9H8O4 + H2O
When 19 g of C7H6O3 and 19 g of C4H6O3
react, which is the limiting reagent?
            
        2C7H6O3 + C4H6O3 −→ 2C9H8O4 + H2O
When 19 g of C7H6O3 and 19 g of C4H6O3
react, which is the limiting reagent?
Answers
                    Answered by
            DrBob222
            
    mols SA = 19/molar mass SA.
mols AA = 19/molar mass AA.
Convert mols of SA to mols of aspirin (use the coefficients in the equation).
Convert mols AA to mols of aspirin(use the coefficients here too).
The reagent giving the smallest number for mols aspirin is the limiting reagent and the smallest number is the correct value for mols aspirin formed in the reaction.
    
mols AA = 19/molar mass AA.
Convert mols of SA to mols of aspirin (use the coefficients in the equation).
Convert mols AA to mols of aspirin(use the coefficients here too).
The reagent giving the smallest number for mols aspirin is the limiting reagent and the smallest number is the correct value for mols aspirin formed in the reaction.
                    Answered by
            Andrea
            
    How do you convert it to moles of asprin?
    
                    Answered by
            DrBob222
            
    Use the coefficients in the balanced equation.
mols SA x (2 mols aspirin/2 mols SA) = mols SA x 2/2 = ? mols aspirin.
mols AA x (2 mols aspirin/1 mol AA) = mols AA x 2/1 = ? mols aspirin.
    
mols SA x (2 mols aspirin/2 mols SA) = mols SA x 2/2 = ? mols aspirin.
mols AA x (2 mols aspirin/1 mol AA) = mols AA x 2/1 = ? mols aspirin.
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