Question
Aspirin (C9H8O4) is synthesized by reacting salicylic acid (C7H6O3) with acetic anhydride (C4H6O3). The balanced equation is given below.
C7H6O3 + C4H6O3 C9H8O4 + HC2H3O2
What mass of acetic anhydride is needed to completely consume 3.60 x 10^2 g salicylic acid?
i worked out the problem and got 270 but the answer is 370. here is my work.
360g C7H6O3 x 1 mol C7H6O3/138.118 g C7H6O3 x 1 mol C4H6O3/ 1 mol C7H6O3 x 102.088 g C4H6O3/1 mol C4H6O3 = 270g C4H6O3
sorry that looks really confusing but is there something wrong with my conversion factor??
C7H6O3 + C4H6O3 C9H8O4 + HC2H3O2
What mass of acetic anhydride is needed to completely consume 3.60 x 10^2 g salicylic acid?
i worked out the problem and got 270 but the answer is 370. here is my work.
360g C7H6O3 x 1 mol C7H6O3/138.118 g C7H6O3 x 1 mol C4H6O3/ 1 mol C7H6O3 x 102.088 g C4H6O3/1 mol C4H6O3 = 270g C4H6O3
sorry that looks really confusing but is there something wrong with my conversion factor??
Answers
DrBob222
Your work would not look so confusing if you used parentheses. For example,
360 g C6H7O3 x (1 mol C6H7O3/138.118) x .....
Your work looks ok, however, I ran this on my calculator and obtained 266.08 grams. (I also used 138.123 instead of 138.118 but I don't think that will make any significant difference). Are you keying this into a database? If so, and 266 doesn't work, I would try 2.66 x 10^2 since the problem was given in scientific notation.
360 g C6H7O3 x (1 mol C6H7O3/138.118) x .....
Your work looks ok, however, I ran this on my calculator and obtained 266.08 grams. (I also used 138.123 instead of 138.118 but I don't think that will make any significant difference). Are you keying this into a database? If so, and 266 doesn't work, I would try 2.66 x 10^2 since the problem was given in scientific notation.
Damon
I agree with you, mol masses 138 and 102
C7H6O3 + C4H6O3 ---> C9H8O4 + HC2H3O2
360/138 or 2.61 mole of C7H6O3
and therefore
2.61 mol of C4H6O3
2.61 = x/102
x = 267
(I did not carry all the decimal places)
C7H6O3 + C4H6O3 ---> C9H8O4 + HC2H3O2
360/138 or 2.61 mole of C7H6O3
and therefore
2.61 mol of C4H6O3
2.61 = x/102
x = 267
(I did not carry all the decimal places)
Mr.TROLL
I agree with you, mol masses 138 and 102
C7H6O3 + C4H6O3 ---> C9H8O4 + HC2H3O2
360/138 or 2.61 mole of C7H6O3
and therefore
2.61 mol of C4H6O3
2.61 = x/102
x = 267
(I did not carry all the decimal places)
C7H6O3 + C4H6O3 ---> C9H8O4 + HC2H3O2
360/138 or 2.61 mole of C7H6O3
and therefore
2.61 mol of C4H6O3
2.61 = x/102
x = 267
(I did not carry all the decimal places)
Mr.TROLL
Your work would not look so confusing if you used parentheses. For example,
360 g C6H7O3 x (1 mol C6H7O3/138.118) x .....
Your work looks ok, however, I ran this on my calculator and obtained 266.08 grams. (I also used 138.123 instead of 138.118 but I don't think that will make any significant difference). Are you keying this into a database? If so, and 266 doesn't work, I would try 2.66 x 10^2 since the problem was given in scientific notation.
360 g C6H7O3 x (1 mol C6H7O3/138.118) x .....
Your work looks ok, however, I ran this on my calculator and obtained 266.08 grams. (I also used 138.123 instead of 138.118 but I don't think that will make any significant difference). Are you keying this into a database? If so, and 266 doesn't work, I would try 2.66 x 10^2 since the problem was given in scientific notation.
Mr.TROLL
360g C7H6O3 x 1 mol C7H6O3/138.118 g C7H6O3 x 1 mol C4H6O3/ 1 mol C7H6O3 x 102.088 g C4H6O3/1 mol C4H6O3 = 270g C4H6O3