Asked by zoya
a diagram shows a cross section of a triangular prism.
AB=BC=7cm. BM=5cm
m is the midpoint of the line segment AC.
a) explain why angle AMB must be a right angle.
b) calculate angle BCM.
c) calculate area of the triangle
AB=BC=7cm. BM=5cm
m is the midpoint of the line segment AC.
a) explain why angle AMB must be a right angle.
b) calculate angle BCM.
c) calculate area of the triangle
Answers
Answered by
Steve
ABC is an isosceles triangle, so the altitude BM intersects AC in the middle.
cos BCM = 5/7
area = 1/2 AC * BM
cos BCM = 5/7
area = 1/2 AC * BM