Asked by arcos15
A car is moving in the +x direction with the following position equation of motion: x = 5.41(m/s)t - 2.7(m/s^2)t^2.
(a) What is the initial velocity of the car?
5.41 m/s
(b) What is the acceleration of the car?
-5.4 m/s^2
(c) At what time does the car come to rest?
__________ s
(d) At what time does the car stop "decelerating?"
__________ s
NEED HELP WITH (C) AND (D)
(a) What is the initial velocity of the car?
5.41 m/s
(b) What is the acceleration of the car?
-5.4 m/s^2
(c) At what time does the car come to rest?
__________ s
(d) At what time does the car stop "decelerating?"
__________ s
NEED HELP WITH (C) AND (D)
Answers
Answered by
Henry
a. Correct.
b. Correct
c. V = Vo + at.
t = (V-Vo)/a = (0-5.41)/-2.7 = 2.0 s.
d. T = 2 s. = Stop time.
the car decelerates until it stops
b. Correct
c. V = Vo + at.
t = (V-Vo)/a = (0-5.41)/-2.7 = 2.0 s.
d. T = 2 s. = Stop time.
the car decelerates until it stops
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