Asked by michelle
Differentiate.
y = x^3/3 − x^2
y = x^3/3 − x^2
Answers
Answered by
Steve
what's the problem? A simple power rule exercise:
y = 1/3 x^3 - x^2
y' = 1/3 * 3 * x^(3-1) - 2*x^(2-1)
= x^2 - 2x
y = 1/3 x^3 - x^2
y' = 1/3 * 3 * x^(3-1) - 2*x^(2-1)
= x^2 - 2x
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