Asked by Ashley

Average rate of change:
h(x)= x^3 -0.5e^x at [0,1]

Answers

Answered by Ashley
The 1/2 should be 1/3, sorry
Answered by Steve
If you mean that the 0.5 should be 1/3, then

h(x) = x^3 - 1/3 e^x
h(0) = -1/3
h(1) = 1 - e/3

so, avg rate of change is (h(1)-h(0))/(1-0) = 4/3 - e/3
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