Asked by zianna
what is the acceleration of a point on the time of a flywheel 0.90 m in diameter, turning at the rate of 1200 rev/min?
Answers
Answered by
drwls
1200 rev/min = 20 rev/s = 12.57 rad/s
Call that the angular speed, w.
The centripetal acceleration is R*w^2.
R is the 0.45 m radius.
a = 0.45*(12.57)^2 = ___ m/s^2
Call that the angular speed, w.
The centripetal acceleration is R*w^2.
R is the 0.45 m radius.
a = 0.45*(12.57)^2 = ___ m/s^2