Asked by Anne
Find the polar coordinates of (8, –8) for r > 0.
Answers
Answered by
Reiny
r^2 = 64+64 = 128
r = 8√2
(8,-8) is in IV and tanØ=-1
Ø = 315° or 7π/4
(x,y) ----> (r,Ø)
(8,-8) ---> (8√2 , 7π/4)
r = 8√2
(8,-8) is in IV and tanØ=-1
Ø = 315° or 7π/4
(x,y) ----> (r,Ø)
(8,-8) ---> (8√2 , 7π/4)
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