Question
Find the polar coordinates for point P which has Cartesian coordinates
(1,-√3)
a) (1,5pi/6)
b) (1,5pi/3)
c) (√3,5pi/3)
d) (2,5pi/3)
(1,-√3)
a) (1,5pi/6)
b) (1,5pi/3)
c) (√3,5pi/3)
d) (2,5pi/3)
Answers
R_Scott
x^2 + y^2 = r^2
oobleck
tanθ = y/x
make sure you get the proper quadrant by checking the signs of x and y.
make sure you get the proper quadrant by checking the signs of x and y.
Alice
answer A?
Alice
(1,5pi/6)???
R_Scott
i refer you, again, to ... x^2 + y^2 = r^2
1^2 + (-√3)^2 = 1 + 3 = 4 = r^2
only one answer fits
1^2 + (-√3)^2 = 1 + 3 = 4 = r^2
only one answer fits