Asked by Lauren
An aqueous solution of a non electrolyte boils at 100.32 degrees C. The expected freezing point for this solution is ______?
(Kb water = 0.512 degrees Cm^-1, Kf water= 1.86 Degree C m^-1)
a. 0 Degrees
b. -0.32
c. -0.83
d. -1.16
e insufficient information
(Kb water = 0.512 degrees Cm^-1, Kf water= 1.86 Degree C m^-1)
a. 0 Degrees
b. -0.32
c. -0.83
d. -1.16
e insufficient information
Answers
Answered by
drwls
d. The lowering effect upon the freezing point due to a solvent is 1.86/0.512 = 3.63 times the boiling point raising effect. Multiply -3.63 by 0.32 C to get the lowering.
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