Asked by Simran kaur

The area of trapezium is 270cmsq. Nd its height is 6cm.if one of parallel sides is double the other,find the two parallel sides.
Ans is 30nd60cm

Answers

Answered by Henry
B2 = 2B1.
A = 0.5(B!+2B!)6 = 270cm^2.
9B1 = 270
B1 = 30 cm.
B2 = 2*30 = 60 cm.
We know that, " Area of trapezium=1/2 * height * sum of parallel sides".

Let, one parallel side=x cm
Then the other parallel side=2x cm

So that,

Area=1/2 * 6 * (x+2x)=270
~ 9x=270
X=30
Hence,
Parallel sides are 30cm and 60cm.
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