Asked by Simran kaur
The area of trapezium is 270cmsq. Nd its height is 6cm.if one of parallel sides is double the other,find the two parallel sides.
Ans is 30nd60cm
Ans is 30nd60cm
Answers
Answered by
Henry
B2 = 2B1.
A = 0.5(B!+2B!)6 = 270cm^2.
9B1 = 270
B1 = 30 cm.
B2 = 2*30 = 60 cm.
A = 0.5(B!+2B!)6 = 270cm^2.
9B1 = 270
B1 = 30 cm.
B2 = 2*30 = 60 cm.
Answered by
PAWAN PATWA (BHATPAR RANI, DEORIA, UP)
We know that, " Area of trapezium=1/2 * height * sum of parallel sides".
Let, one parallel side=x cm
Then the other parallel side=2x cm
So that,
Area=1/2 * 6 * (x+2x)=270
~ 9x=270
X=30
Hence,
Parallel sides are 30cm and 60cm.
Let, one parallel side=x cm
Then the other parallel side=2x cm
So that,
Area=1/2 * 6 * (x+2x)=270
~ 9x=270
X=30
Hence,
Parallel sides are 30cm and 60cm.
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