Asked by Jane

Algebra BD bisects <ABC. Solve for x and find m<ABC.

m<ABD = 4x - 16, m<CBD = 2x + 6

Please teach me how to work this.
Answered by Steve
since BD bisects <ABC, m<ABD = m<DBC

4x-16 = 2x+6
2x = 22
x = 11

m<ABC = m<ABD + m<DBC = 4*11-16 + 2*11+6 = 28+28 = 56
Answered by Jane
Steve, thank you so much. You explained it so I could understand it.
Answered by Steve
That's the plan. :-)
Answered by Arooj
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10007
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