Asked by eyeda
algebra 1b solve y^2+10y+25=121?
Answers
Answered by
Damon
y^2 + 10 y - 96 = 0
96/6 = 16
(y+16)(y-6) = 0
y = 6
or
y = -16
96/6 = 16
(y+16)(y-6) = 0
y = 6
or
y = -16
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