Give the base-ten numeral for 101,010two and 912twelve

Answer 1

(0 * 2^0) + (1 * 2^1) + (0 * 2^2) + (1 * 2^3) + (0 * 2^4) + (1 * 2^5)

0 + 2 + 0 + 8 + 0 + 32 = 42

(2 * 12^0) + (1 * 12^1) + (9 * 12^2)

2 + 12 + 1296 = 1310