Asked by Kali

The best leaper in the animal kingdom is the puma, which can jump to a height of 3.7 m when leaving the ground at an angle of 45°. With what speed must the animal leave the ground to reach that height?
_____m/s
Answered by Scott
the potential energy at the top of the leap is equal to the (vertical) kinetic energy at the start

m * g * h = .5 * m * [v * sin(45º)]^2

the m's cancel

(2 * g * h) / [sin(45º)]^2 = v^2

g = 9.8 m/s^2

145 = v^2

Answered by bubs
What minimum speed does a 170 puck need to make it to the top of a 3.5 -long, 23 frictionless ramp?
There are no AI answers yet. The ability to request AI answers is coming soon!