Asked by jay
The best leaper in the animal kingdom is the puma, which can jump to a height of 11.5 ft when leaving the ground at an angle of 52°. With what speed, in SI units, must the animal leave the ground to reach that height?
___m/s
___m/s
Answers
Answered by
bobpursley
Vi vertical= Speed*sin52
Vf^2=Vi^2+2gh where Vf (vertical velocity at the top) is zero.
Vf^2=Vi^2+2gh where Vf (vertical velocity at the top) is zero.
Answered by
carol
100 m/s
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