Asked by e
Which animal is often used to model human body systems?(1 point)
Responses
sheep
sheep
rabbit
rabbit
cow
cow
pig
Responses
sheep
sheep
rabbit
rabbit
cow
cow
pig
Answers
Answered by
GPT-4o mini
The animal often used to model human body systems is the pig. Pigs have physiological and anatomical similarities to humans, making them valuable in research for understanding various biological processes and diseases.
Answered by
e
Alternation of generations in plants permits(1 point)
Responses
neither mitosis nor meiosis.
neither mitosis nor meiosis.
only meiosis.
only meiosis.
only mitosis.
only mitosis.
both mitosis and meiosis.
Responses
neither mitosis nor meiosis.
neither mitosis nor meiosis.
only meiosis.
only meiosis.
only mitosis.
only mitosis.
both mitosis and meiosis.
Answered by
GPT-4o mini
The correct response is **both mitosis and meiosis**.
In the alternation of generations, plants alternate between the gametophyte (haploid) stage, which mainly involves mitosis to produce gametes, and the sporophyte (diploid) stage, where meiosis occurs to produce spores.
In the alternation of generations, plants alternate between the gametophyte (haploid) stage, which mainly involves mitosis to produce gametes, and the sporophyte (diploid) stage, where meiosis occurs to produce spores.
Answered by
e
Unlike ferns, angiosperms use ________ to contain their embryos.(1 point)
Responses
sporangium
sporangium
spores
spores
seeds
seeds
pollen
Responses
sporangium
sporangium
spores
spores
seeds
seeds
pollen
Answered by
GPT-4o mini
Unlike ferns, angiosperms use **seeds** to contain their embryos.
Answered by
e
Use the scenario to answer the question.
Scenario: You observe the growth of a group of plants that have been tipped over.
How will auxin influence cell growth in the roots of these plants?
(1 point)
Responses
Auxin will build up on the upper side of the root and stimulate cell growth.
Auxin will build up on the upper side of the root and stimulate cell growth.
Auxin will build up on the upper side of the root and inhibit cell growth.
Auxin will build up on the upper side of the root and inhibit cell growth.
Auxin will build up on the lower side of the root and stimulate cell growth.
Auxin will build up on the lower side of the root and stimulate cell growth.
Auxin will build up on the lower side of the root and inhibit cell growth.
Auxin will build up on the lower side of the root and inhibit cell growth.
Scenario: You observe the growth of a group of plants that have been tipped over.
How will auxin influence cell growth in the roots of these plants?
(1 point)
Responses
Auxin will build up on the upper side of the root and stimulate cell growth.
Auxin will build up on the upper side of the root and stimulate cell growth.
Auxin will build up on the upper side of the root and inhibit cell growth.
Auxin will build up on the upper side of the root and inhibit cell growth.
Auxin will build up on the lower side of the root and stimulate cell growth.
Auxin will build up on the lower side of the root and stimulate cell growth.
Auxin will build up on the lower side of the root and inhibit cell growth.
Auxin will build up on the lower side of the root and inhibit cell growth.
Answered by
GPT-4o mini
In the scenario where plants are tipped over, **auxin will build up on the lower side of the root and inhibit cell growth**. This differential distribution of auxin causes the cells on the lower side of the root to elongate less, allowing the roots to grow downward.
Answered by
e
Dialysis bags can be used as models of cells to explore the movement of materials into and out of cells. Students set up an investigation with a dialysis bag containing a 2% iodine solution in a beaker containing a 9% starch solution as shown in the figure. Starch turns blue-black in the presence of iodine. The dialysis bag is permeable to water and iodine but not to starch.
Which two observations most accurately predict what will occur in the investigation?
(4 points)
Responses
The solution in the beaker will turn blue-black.
The solution in the beaker will turn blue-black.
The concentration of starch in the dialysis bag will increase.
The concentration of starch in the dialysis bag will increase.
The mass of the dialysis bag will decrease.
The mass of the dialysis bag will decrease.
The solution in the dialysis bag will turn blue-black.
The solution in the dialysis bag will turn blue-black.
The mass of the dialysis bag will increase.
Which two observations most accurately predict what will occur in the investigation?
(4 points)
Responses
The solution in the beaker will turn blue-black.
The solution in the beaker will turn blue-black.
The concentration of starch in the dialysis bag will increase.
The concentration of starch in the dialysis bag will increase.
The mass of the dialysis bag will decrease.
The mass of the dialysis bag will decrease.
The solution in the dialysis bag will turn blue-black.
The solution in the dialysis bag will turn blue-black.
The mass of the dialysis bag will increase.
Answered by
GPT-4o mini
In the scenario described, the two observations that most accurately predict what will occur in the investigation are:
1. **The solution in the beaker will turn blue-black.** (Iodine will diffuse into the beaker and react with starch.)
2. **The mass of the dialysis bag will increase.** (Water will move into the dialysis bag due to osmosis, and the concentration of starch will not change as starch cannot leave the bag.)
These predictions are based on the movement of iodine and water through the dialysis bag and how they interact with the substances in the beaker.
1. **The solution in the beaker will turn blue-black.** (Iodine will diffuse into the beaker and react with starch.)
2. **The mass of the dialysis bag will increase.** (Water will move into the dialysis bag due to osmosis, and the concentration of starch will not change as starch cannot leave the bag.)
These predictions are based on the movement of iodine and water through the dialysis bag and how they interact with the substances in the beaker.
Answered by
e
The models below are set up to represent how a cell responds to imbalances in solute concentration. Match the correct arrow set to the appropriate beaker to show how water will move into or out of the cell in each beaker for the solute conditions shown.(9 points)
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Beaker 1
Beaker 2
Beaker 3
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Beaker 1
Beaker 2
Beaker 3
Answered by
GPT-4o mini
To accurately determine how water will move into or out of cells placed in different solute concentration conditions, we can generally categorize the scenarios as follows:
1. **Isotonic Solution (Equal solute concentration inside and outside the cell)**: No net movement of water into or out of the cell.
2. **Hypotonic Solution (Lower solute concentration outside the cell)**: Water will move into the cell, causing it to swell.
3. **Hypertonic Solution (Higher solute concentration outside the cell)**: Water will move out of the cell, causing it to shrink.
Based on this understanding, here’s how you would match the arrows to the beakers:
- **Beaker 1** (Hypotonic): Use an arrow pointing into the cell, indicating water moving in.
- **Beaker 2** (Isotonic): Use a neutral set of arrows (no arrows or equal arrows pointing in both directions), indicating no net movement of water.
- **Beaker 3** (Hypertonic): Use an arrow pointing out of the cell, indicating water moving out.
Make sure to drag the correct arrows according to these descriptions to the appropriate beaker. If you want to specify exact images or arrow sets, please provide those.
1. **Isotonic Solution (Equal solute concentration inside and outside the cell)**: No net movement of water into or out of the cell.
2. **Hypotonic Solution (Lower solute concentration outside the cell)**: Water will move into the cell, causing it to swell.
3. **Hypertonic Solution (Higher solute concentration outside the cell)**: Water will move out of the cell, causing it to shrink.
Based on this understanding, here’s how you would match the arrows to the beakers:
- **Beaker 1** (Hypotonic): Use an arrow pointing into the cell, indicating water moving in.
- **Beaker 2** (Isotonic): Use a neutral set of arrows (no arrows or equal arrows pointing in both directions), indicating no net movement of water.
- **Beaker 3** (Hypertonic): Use an arrow pointing out of the cell, indicating water moving out.
Make sure to drag the correct arrows according to these descriptions to the appropriate beaker. If you want to specify exact images or arrow sets, please provide those.