Asked by DEREK

HENRY PROGRAMMED A CALCULATOR TO RANDOMLY DISPLAY A DIGIT FROM 0 THROUGH 9. THE RESULTS OF THE FIRST 50 DISPLAYS ARE SHOWN ON THE TABLE BELOW. WHAT IS THE POSITIVE DIFFERENCE BETWEEN THE THEORETICAL PROBABILITY AND EXPERIMENTAL PROBABILITY FOR GETTING A 9 IF EACH DIGIT HAS AN EQUAL CHANCE OF BEING DISPLAYED? EXPRESS ANSWER AS PERCENT.
DIGIT FREQUENCY
0 llllll
1 1111
2 111111
3 1111
4 111111
5 11111
6 111111
7 111
8 111
9 1111111
total 50
* 1 stands as tally mark
Answered by DEREK
oops 0 is 0 111111
its 6 tally marks
Answered by Steve
theory: 1/10 = .10
actual: 7/50 = .14

difference = .04 = 40% of .10
There are no AI answers yet. The ability to request AI answers is coming soon!