a) 13.2
13.2^2=6.6^2+2(4.95)(ΔX)
174.24= 43.56+9.9ΔX
130.68=9.9ΔX
ΔX=13.2
b)6.6+13.2/2=13.2/t
9.9=13.2/t
t= 1.33
An object moves with constant acceleration 4.95 m/s2 and over a time interval reaches a final velocity of 13.2 m/s.
(a) If its initial velocity is 6.6 m/s, what is its displacement during the time interval?
(b) What is the distance it travels during this interval?
1 answer
1 answer