solve the following logarithm equation

Question

log (4x+7)=1+log(x-6)

x=?

please show work

Answer 1

log (4x+7)=1+log(x-6)
log (4x+7) - log(x-6) = 1
log [(4x+7)/(x-6)] = 1
(4x+7)/(x-6) = 10^1 = 10
10x - 60 = 4x + 7
6x = 67
x = 67/6