Asked by Anew
A circle has the equation
x^2+y^2+6x-46=0
graph using (h,k) radius r
what are the intercept?
Answers
Answered by
Damon
x^2 + 6 x = -y^2 + 46
x^2 + 6 x + 9 = -y^2 + 55
(x+3)^2 = -y^2 + 55
(x+3)^2 + (y-0)^2 = 55
center at (-3, 0) radius = sqrt(55)
x^2 + 6 x + 9 = -y^2 + 55
(x+3)^2 = -y^2 + 55
(x+3)^2 + (y-0)^2 = 55
center at (-3, 0) radius = sqrt(55)
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