Question

a circle has the equation 3(x-5)^2_3y^2=12. Find the center and radius and graph the circle. find the intercepts, if any.

plz show work

Answer 1

Shouldn't there be a + sign between the 2 and the 3? What you have written is not the equation of a circle.

Answer 2

Yes, my mistake.find the center, radius and graph of circle. then find intercepts

3(x-5)^2+3y^2=12

plz show work

Answer 3

divide everybody by 3

(x-5)^2 + y^2 = 4

centre : (5,0), radius 2

clearly the circle can't reach the y-axis,
(let x= 0, ---> 75 + 3y^2 = 12
3y^2 = - .... , not possible)

for the x-intercepts , let y = 0
3(x-5)^2 = 12
(x-5)^2 = 4
x-5 = ± 2
x = 7 or x = 3

Answer 4

Convert:
TT/3 rad to degrees