Asked by Nick
The reaction of 9.3 grams of fluorine with
excess chlorine produced 4.1 grams of ClF3.
What percent yield of ClF3 was obtained?
excess chlorine produced 4.1 grams of ClF3.
What percent yield of ClF3 was obtained?
Answers
Answered by
DrBob222
1. Write and balance the equation.
2. Convert 9.3 g F2 to mols. mols = grams/molar mass.
3. Using the coefficients in the balanced equation, convert mols F2 to mols of the product.l
4. Now convert mols or the product to grams. g = mols x molar mass. This is the theoretical yield(TE). Actual yield is 4.1g.
5. %yield = (actual yield/TE)*100 = ?
2. Convert 9.3 g F2 to mols. mols = grams/molar mass.
3. Using the coefficients in the balanced equation, convert mols F2 to mols of the product.l
4. Now convert mols or the product to grams. g = mols x molar mass. This is the theoretical yield(TE). Actual yield is 4.1g.
5. %yield = (actual yield/TE)*100 = ?
Answered by
Anonymous
hyghygyuj
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