The reaction of 9.3 grams of fluorine with

excess chlorine produced 4.1 grams of ClF3.
What percent yield of ClF3 was obtained?

2 answers

1. Write and balance the equation.
2. Convert 9.3 g F2 to mols. mols = grams/molar mass.
3. Using the coefficients in the balanced equation, convert mols F2 to mols of the product.l
4. Now convert mols or the product to grams. g = mols x molar mass. This is the theoretical yield(TE). Actual yield is 4.1g.
5. %yield = (actual yield/TE)*100 = ?
hyghygyuj
Similar Questions
  1. The reaction of 9.5 grams of fluorine withexcess chlorine produced 5.9 grams of ClF3. What percent yield of ClF3 was obtained?
    1. answers icon 2 answers
  2. The reaction of 5.3 grams of fluorine withexcess chlorine produced 4.6 grams of ClF3. What percent yield of ClF3 was obtained?
    1. answers icon 1 answer
    1. answers icon 0 answers
  3. The reaction of 8 grams of fluorine with excesschlorine produced 6.4 grams of ClF3. What percent yield of ClF3 was obtained?
    1. answers icon 2 answers
more similar questions