Asked by stoic-rider77

Landing with a speed of 78.3 m/s, and traveling due south, a jet comes to rest in 959 m. Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.

Answers

Answered by charrice
initial velocity = 78.3 m/s
final velocity = 0 m/s
distance traveled - 959 m
a = ?

use
(final velocity)^2 = (initial velocity)^2 + 2ad

solve equation for 'a'.
Answered by Anonymous
3.2
Answered by TK
3.2 m/s^2
Answered by Anonymous
omg
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