Asked by Sally
Landing with a speed of 90 m/s In the x direction a jet come to rest at 1 km. assuming the jet slows down with constant acceleration find the magnitude of it's acceleration. Is there anyway someone could break this down step by step??
Answers
Answered by
Damon
distance = 1000 meters
average speed = 90/2 = 45 meters/second
so it took 1000/45 = 22.2 seconds to stop
acceleration = change in velocity/change in time
a = (0 - 90)/22.2 = - 4.05 m/s^2
average speed = 90/2 = 45 meters/second
so it took 1000/45 = 22.2 seconds to stop
acceleration = change in velocity/change in time
a = (0 - 90)/22.2 = - 4.05 m/s^2
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