Asked by bobby
Use part I of the Fundamental Theorem of Calculus to find the derivative of
g(x)= integrate from 9x to 4x of ((u+4)/(u-1))du
g(x)= integrate from 9x to 4x of ((u+4)/(u-1))du
Answers
Answered by
Steve
since (u+4)/(u-1) = 1 + 5/(u-1)
integral = u + 5log u [9x,4x]
-5(x - log(4x-1) + log(9x-1))
integral = u + 5log u [9x,4x]
-5(x - log(4x-1) + log(9x-1))
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