Question

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.
g(x) = e^(3t^2) − 3t dt from 4 to x

Answer 1

Hmmm. Your question is ill worded. I suspect you mean g(x) is the integral of e^(3t^2)-3t dt from 4 to x.

Otherwise, we'd need the integral of e^(3t^2) which is not elementary.

So, with that in mind,

dg/dx = e^(3x^2)-3x