Asked by dave
divide and simplify
(y^3-3y)/(y^2-9)divided by
(y^2-7y-30)/(y^2+6y+9)
Please help!
(y^3-3y)/(y^2-9)divided by
(y^2-7y-30)/(y^2+6y+9)
Please help!
Answers
Answered by
Henry
(y^3-3y)/(y^2-9)*(y^2+6y+9)/(y^2-7y-30)=
(y(y^2-3)/(y+3)(y-3))*(y+3)(y+3)/(y+3)(y-10)=((y^2-3)/(y-3)*1/(y-10)=
(y^2-3)/(y-3)(y-10)
NOTE: All "(y+3)s" cancelled.
(y(y^2-3)/(y+3)(y-3))*(y+3)(y+3)/(y+3)(y-10)=((y^2-3)/(y-3)*1/(y-10)=
(y^2-3)/(y-3)(y-10)
NOTE: All "(y+3)s" cancelled.
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