Asked by Jeconiah
The displacement of a particle is given by: x=t^3-7/2t^2+2t-1. Find the particles initial displacement. And find when the particle is at rest.
Answers
Answered by
Steve
initially, t=0, so x = -1
particle is at rest when dx/dt = 0
dx/dt = 3t^2 - 7t + 2
dx/dt=0 when t = 1/3 or 2
particle is at rest when dx/dt = 0
dx/dt = 3t^2 - 7t + 2
dx/dt=0 when t = 1/3 or 2
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