Asked by Cindy
What is the displacement from a starting position of (14.0,3.0)m to a final position of (-3.0,-4.0) m?
Answers
Answered by
Damon
change in y = -7
change in x = -17
magnitude of displacement = sqrt(7^2+17^2)
tan of angle below -x axis = 7/17
because in third quadrant where x and y are negative
change in x = -17
magnitude of displacement = sqrt(7^2+17^2)
tan of angle below -x axis = 7/17
because in third quadrant where x and y are negative
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