Asked by Anonymous
Standing on the top ledge of a 55 m high building you throw a ball straight up with an initial speed of 29 m/s. How long to the nearest second, does it take to hit the ground?
Answer after rounding is 7 seconds.
The next question is "If the building in the previous problem is 44 meters high and you throw the ball up at 30 m/s, how high to the nearest meter does it go?"
I don't understand how to figure out what the highest meter is.
Answer after rounding is 7 seconds.
The next question is "If the building in the previous problem is 44 meters high and you throw the ball up at 30 m/s, how high to the nearest meter does it go?"
I don't understand how to figure out what the highest meter is.
Answers
Answered by
drwls
Apparently you have already answered question 1. If not, see the "related Question" below.
Question 2:
If the ball starts at a height of Ho = 44 m, if loses the available kinetic energy until it reaches the maximum height Hmax
g*Ho + Vo^2/2 = g*Hmax
(Hmax-Ho)= Vo^2/(2g) = 45.9 m
Hmax = 89.9 m
Question 2:
If the ball starts at a height of Ho = 44 m, if loses the available kinetic energy until it reaches the maximum height Hmax
g*Ho + Vo^2/2 = g*Hmax
(Hmax-Ho)= Vo^2/(2g) = 45.9 m
Hmax = 89.9 m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.