Asked by unowen
A stone is dropped from a ledge 45m high. What will its speed on reaching the Earth be?
Answers
Answered by
bobpursley
mgh=1/2 m v^2
PE=KE
v^2=2gh
v= sqrt(2gh)=sqrt(2*9.8*45)=29.7m/s
PE=KE
v^2=2gh
v= sqrt(2gh)=sqrt(2*9.8*45)=29.7m/s
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