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Asked by unowen

A stone is dropped from a ledge 45m high. What will its speed on reaching the Earth be?
7 years ago

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Answered by bobpursley
mgh=1/2 m v^2
PE=KE
v^2=2gh
v= sqrt(2gh)=sqrt(2*9.8*45)=29.7m/s
7 years ago
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A stone is dropped from a ledge 45m high. What will its speed on reaching the Earth be?

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