Question

Write the equation of a circle in standard Find the center, radius intercepts and graph the circle. .........x^2+y^2-12x-4y+36=0

Answer 1

x^2 -12 x = -y^2 + 4 y -36

x^2 -12 y + 36 = -y^2 + 4 y

-(x-6)^2 = y^2-4y

-(x-6)^2 + 4 = y^2 - 4 y + 4
-(x-6)^2 + 4 = (y-2)^2

(x-6)^2 + (y-2)^2 = 4

center at (6,2) radius 2
you do the rest

Answer 2

Find the center (h,k) and the radius r of the circle
5x2−8x+5y2−5y−6=0.