Asked by Peluche
Write the equation of circle O centered at origin that passes through (9,-2)
Circle B with center (0,-2) that passes through (-6,0)
>For circle B, is the radius 6 in this case? So equation would be x^2+(x+2)^2=36, correct?
If this is the case, how would I solve for circle O?
Circle B with center (0,-2) that passes through (-6,0)
>For circle B, is the radius 6 in this case? So equation would be x^2+(x+2)^2=36, correct?
If this is the case, how would I solve for circle O?
Answers
Answered by
Steve
center at the origin means
x^2 + y^2 = r^2
9^2 + (-2)^2 = 81+4 = 85, so the circle is
x^2 + y^2 = 85
center at (0,-2) means
x^2 + (y+2)^2 = r^2
(-6)^2 + (0+2)^2 = 36+4 = 40
x^2 + (y+2)^2 = 40
x^2 + y^2 = r^2
9^2 + (-2)^2 = 81+4 = 85, so the circle is
x^2 + y^2 = 85
center at (0,-2) means
x^2 + (y+2)^2 = r^2
(-6)^2 + (0+2)^2 = 36+4 = 40
x^2 + (y+2)^2 = 40
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